What is resonance in an LCR series circuit? | vedclass

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Question

(D) In an $LCR$ series circuit,resonance occurs when the inductive reactance $(X_L = \omega L)$ is equal to the capacitive reactance $(X_C = 1/(\omega

Vedclass · Accepted Answer

Both $B$ and $C$.

Vedclass · Answer

(D) In an $LCR$ series circuit,resonance occurs when the inductive reactance $(X_L = \omega L)$ is equal to the capacitive reactance $(X_C = 1/(\omega C))$.This condition implies $X_L = X_C$,which leads to $\omega L = 1/(\omega C)$,or $\omega^2 = 1/(LC)$.At this frequency,the net reactance of the circuit is zero $(X = X_L - X_C = 0)$.Consequently,the impedance of the circuit becomes equal to the resistance $(Z = R)$,which is the minimum possible impedance.Since $Z$ is minimum,the current in the circuit $(I = V/Z)$ reaches its maximum value.Because the net reactance is zero,the phase angle between voltage and current is zero,meaning the circuit behaves as a purely resistive circuit.

What is resonance in an $LCR$ series circuit?

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